Now, let’s say an initial solution (1) has n1 moles (so n1 = C1V1), if the solution is diluted, which means more solvent is added, the same number of moles will be present in the final solution (2), which we can denote as n2 (so n2 = C2V2).Īs the number of moles of the initial and final solution is the same, n1 = n2 and subsequently, C1V1 = C2V2, this is the dilution formula. Recall the molarity formula, C=n/V, if we arrange this to make moles the subject: n = CV. This next video goes through the molarity formula as well, have a look if you’re still confused or to see if you can understand it in a different context. (Note that this video spells litre like liter, don’t spell it like that.) Last post we introduced concentration, this video will go in a little more depth and introduce the molarity formula C=n/V (concentration = (moles of solute) / (volume of solution)). Dilutions (number of moles before dilution = number of moles of sample after dilution).Manipulate variables and solve problems to calculate concentration, mass or volume using:.This post will go through some formulae applied to find and manipulate concentrations for Prelim Chemistry.
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